Question

(i) Draw a line segment AB of length 3 cm. ( ii )Now, draw an angle XAB = 90° at point A of line segment AB. (iii) Cut a line segment AD = 3 cm from the ray AX and join BD. (iv) Now, D point C is at a distance of 3 cm. So, having D as the center, draw an arc of radius 3 cm (v) From B, point C is at a distance of 3 cm. So, having 8 as the center, draw an arc of radius 3 cm which intersects the previous arc (obtained in step iv) at C.
(vi) Join DC and BC.
Thus, ABCD is the required Quadrilateral of side 3 cm.


Q1.Name the quadrilateral which so obtained from the above steps of construction *

a.Square
b.Rectangle
c.Parallelogram
d.Rhombus​

Answer 1

Answer:

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