Question

I draw a square with side 6cm. and I draw a triangle with equal area of that square,​

Answer 1

$\huge{\green{\bigstar{\mathfrak{hi \: mate{\bigstar}}}}}$

A. Draw the given square ABCD.

B. Draw the diagonal DB of square ABCD.

C. Draw a parallel line through point C to diagonal DB of square ABCD which intersects at E produced AB.

D. CE||DB. ΔADE is the required triangle.

Proof:

∆DCB = ∆DBE (on same base DB and between same parallels DB and CE)

∴ ∆DCB = ∆DBE

∆ABD + ∆DCB = ∆DBE + ∆ABD (adding area of ∆ABD on both sides)

∴ square ABCD = ∆ADE

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Answer 2

Step-by-step explanation:

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