Question

I drew a circle with Centre O of which length of radius is 6 cm. A point P is 10 cm away from the centre O of a circle . A tangent PT is drawn. let us write by calculating the length of the Tangent PT. ​

Answer 1

$\star\;\large\bold{\underline{\underline{\sf{\red{Solution}}}}}$

OT is radius and PT is a tangent of circle with Centre O.

In right - angle triangle POT

∴ OT ⊥ PT

$\therefore \: {PT}^{2} = {PO}^{2} - {OT}^{2} sq.cm$

$\large = {PT}^{2} ( {10}^{2} ) - ( {6}^{2} )sq.cm$

$\implies \: (100 - 36)sq.cm$

$\implies \: 64sq.cm$

$\therefore \: PT = \sqrt{64} = 8cm$

∴ The length of the tangent PT is 8cm.

$\star\;\large\bold{\underline{\underline{\sf{\pink{Be brainly}}}}}$