Question

I.E of 1 mole of Na atom is 495 kJ/mole.
How much energy is required for converting 4.6 mg of Na into Na+ ions?

Answer 1

Gram molecular weight of Na = 23 g

Given that -
23 g ----> 495 kJ

Number of moles (n) = Given weight/ Gram atomic weight

n = 4.6 x 10⁻³/23

Energy required = 4.6 x 10⁻³ x 495 x 10³/23 = 99 kJ

Hope This Helps You!

Answer 2

Gram molecular weight of Na
                                            = 23 g

Given, 
      23 g ⇒  495 kJ

Number of moles = Given weight/ Gram atomic weight
             n = 4.6 x 10-³/23

Energy required = 4.6 x 10-³ x 495 x 10³/23
                          = 99 kJ


Hope it helps ^_^