I) Evaluate the following limit
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Ans----> - √3 / 6
Solution--->
(1) plzzz refer the attachement
(2) In second step we take 2 common from the numerator
(3) In third step we put
1 / 2 = Sin π / 6
(4) In 4th step we apply a formula
SinC - SinD = 2 Cos ( C - D / 2 ) Sin ( C- D / 2 )
(5) In 7th step we divide and multiply denominator by 12
(6) In 11th step we put
( 6x - π ) / 12 = h
when x-------> π , h ----------> 0
(7) In 11th step we used a formula of limit
lim ( Sinh / h ) = 1
h----> 0
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√3/6
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