(I) Express the following statements into Linear Equations.
Q.1 Thrice a number decreased by 6 is equal to 27.
Answers
Answer: x+4=9
x=9-4
x= 5
(ii) y-2=8
y=8+2
y=10
(iii) a\times10\ =\ 70a×10 = 70
(iv) \frac{b}{5}=\ 6\
5
b
= 6
b= 30
(v) \frac{3}{4}\times t\ =\ 15\
4
3
×t = 15
t\ =\ 15\times\frac{4}{3}t = 15×
3
4
t = 20
(vi) \frac{b}{5}=\ 6\
5
b
= 6
b\ =\ 6\ \times5\b = 6 ×5
b = 30
(vii) \left(\frac{1}{4}\times x\right)-\ 4\ =\ 4\(
4
1
×x)− 4 = 4
\frac{x}{4}-\ 4\ =\ 4\
4
x
− 4 = 4
\frac{x}{4}=4+4\
4
x
=4+4
x\ =\ 8\times4x = 8×4
x= 32
(viii) 6y-6 = 60
6y = 60+6
6y = 66
y\ =\ \frac{60}{6}y =
6
60
y = 11
(ix) \frac{z}{3}+\ 3\ =\ 30\
3
z
+ 3 = 30
\frac{z}{3\ }=\ 33
3
z
= 33
z\ =\ 33\times3z = 33×3
z = 99
Step-by-step explanation:
Answer:
Express the following statements into Linear Equations.
Q.1 Thrice a number decreased by 6 is equal to 27.
the number = x
3x-6=72