Question

İf 2 =p^3,then 8p must equal

Answer 1

Answer:

$10.08$

ans 10.08

Answer 2

SOLUTION

GIVEN

2 = p³ then 8p must equal

$\sf(A) \: \: {p}^{6}$

$\sf(B) \: \: {p}^{8}$

$\sf(C) \: \: {p}^{10}$

$\sf(D) \: \: 8 \sqrt{2}$

FORMULA TO BE IMPLEMENTED

We are aware of the formula on indices that :

‌$\sf{1. \: \: {a}^{m} \times {a}^{n} = {a}^{m + n} }$

‌$\displaystyle \sf{2. \: \: \: \frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n} }$

‌$\displaystyle \sf{3. \: \: \: { ({a}^{m} )}^{n} = {a}^{mn} }$

‌$\displaystyle \sf{4. \: \: {a}^{0} = 1}$

‌

EVALUATION

Here it is given that

$\displaystyle \sf{ 2 = {p}^{3} }$

$\displaystyle \sf{ \implies {p}^{3} = 2 }$

$\displaystyle \sf{ \implies {( {p}^{3} )}^{3} = {2}^{3} }$

$\displaystyle \sf{ \implies {p}^{3 \times 3} = {2}^{3} }$

$\displaystyle \sf{ \implies {p}^{9} = 8 }$

Now 8p

$\displaystyle \sf{ = 8 \times p}$

$\displaystyle \sf{ = {p}^{9} \times p}$

$\displaystyle \sf{ = {p}^{9} \times {p}^{1} }$

$\displaystyle \sf{ = {p}^{9 + 1} }$

$\displaystyle \sf{ = {p}^{10} }$

FINAL ANSWER

Hence the correct option is

$\sf(C) \: \: {p}^{10}$

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