Question

I'f a +b+C =-9 and ab + BC + CA =26. Find a^2 +b^2 + c^2


plz help me guys
very urgent​

Answer 1

Step-by-step explanation:

(a+b+c)^2= a^2+b^2+c^2+2ab+2bc+2ca

(-9)^2- 2(26)=a^2+b^2+c^2

=81-52

=29

Answer 2

Answer:

29

Step-by-step explanation:

Given:

a + b +c = - 9

ab + bc + ac = 26

To find:

a² + b² + c²

Solution:

As We know ,

(a + b + c)² = a² + b² + c²+2(ab + bc + ac)

[ Putting the value of a + b + c and ab + bc + ac ]

Or, ( - 9)² = a² + b² + c² + 2(26)

Or, 81 = a² + b² + c² + 52

Or, 81 - 52 = a² + b² + c²

Or, 29 = a² + b² + c²

Hence the required value of a² + b² + c² is 29 .