Question

i) Find k, if f(k) = 2k-1 and fo f(k) = 5.​

Answer 1

Answer:

2

Step-by-step explanation:

given f(k) = 2k-1

fоf(k) = 5

 f(f(k))=5

 f( 2k-1 ) = 5

2(2k-1)-1=5  (∵ f(k) = 2k-1 )

4k-2-1 = 5

4k-3 = 5

4k= 5+3

4k = 8

k = 8÷4

∴ k = 2