Question

I. Find the amount and Compound interest
when the inbest
Compounded annualy
Principal - 4000 , Time- 2years ,rate -10% per annum ​

Answer 1

Answer :-

Given :-

• Principal = Rs. 4000
• Time = 2 years
• Rate = 10% p.a.

To find :-

• Amount
• Compound interest

Solution :-

$\implies\sf Amount = P \Big( 1 + \dfrac{R}{100}\Big)^n$

$\implies\sf A = 4000 \times \Big( 1 + \dfrac{1\not0}{10\not0}\Big)^2$

$\implies\sf A = 4000 \times \Big(1 + \dfrac{1}{10}\Big)^2$

$\implies\sf A = 4000 \times \Big(\dfrac{11}{10}\Big)^2$

$\implies\sf A = 40\cancel{00} \times \dfrac{121}{1\cancel{00}}$

$\implies\sf A = 40 \times 121$

$\implies\sf A = 4840$

Amount = Rs. 4840

Compound interest = Amount - Principal

= 4840 - 4000

= 840

Compound interest = Rs. 840

Answer 2

Given :-

• Principal (P) = Rs 4000
• Time (n) = 2 years
• Rate (R) = 10% per annum

To Find :-

• Amount
• Compound interest

Formulas :-

$\red \bigstar \: {\underline{\boxed{\mathcal {\pmb{\quad Amount \: = \: Principal \: \times \bigg(\:1 \: + \: \dfrac{Rate}{100}\bigg)^{n}\quad}}}}}$

$\red \bigstar \: {\underline{\boxed{\mathcal {\pmb{\quad Compound \: Interest \: = \: Amount \: - \: Principal \quad}}}}}$

Solution :-

${:} \longrightarrow \sf \: Amount \: = \: Principal \: \times \bigg(\:1 \: + \: \dfrac{Rate}{100}\bigg)^{n} \\ \\ {:} \longrightarrow \sf \: Amount \: = \: 4000 \: \times \bigg(\:1 \: + \: \dfrac{10}{100}\bigg)^{2} \\ \\ {:} \longrightarrow \sf \: Amount \: = \: 4000 \: \times \bigg(\dfrac{110}{100}\bigg)^{2} \\ \\ {:} \longrightarrow \sf \: Amount \: = \: 4 \cancel{000} \: \times \: \dfrac{110}{1 \cancel{00}} \: \times \: \dfrac{110}{10 \cancel{0}} \\ \\ {:} \longrightarrow \sf \: Amount \: = \: 4 \: \times \: \dfrac{110 \: \times \: 110}{10} \\ \\ {:} \longrightarrow \sf \: Amount \: = \: 4 \: \times \: \dfrac{12100}{10} \\ \\{:} \longrightarrow \sf \: Amount \: = \: 4 \: \times \: 1210 \\ \\ {:} \longrightarrow \underline{\boxed{\sf \: Amount \: = \: Rs \: 4840}} \: \blue \bigstar$

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$\longmapsto {\pmb{ Compound \: Interest \: = \: Amount \: - \: Principal} } \\ \\ \longmapsto {\sf{ Compound \: Interest \: = \: 4840 \: - \: 4000} } \\ \\ \longmapsto \underline{\boxed{\pmb{ \red{ Compound \: Interest \: = \:Rs \:840} }}}$

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$\qquad \therefore\: \sf{ Amount \: = \underline {\underline{ Rs \: 4840}}}$

$\qquad \therefore\: \sf{ Compound \: Interest\: = \underline {\underline{ Rs \: 840}}}$

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