Question

(i) Find the current through 6 ohm resistor.
(ii) find the potential difference across 12 ohm resistor

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Answer 1

Given :

• R₁ = 6 Ω
• R₂ = 3 Ω
• R₃ = 3 Ω
• R₄ = 12 Ω
• V = 4 v

To Find :

• Current through 6Ω resistor.
• Potential difference across 12Ω resistor.

According to the question,

i) 6Ω and 3Ω are connected in series. So,

➞ R = R₁ + R₂

➞ R = 6Ω + 3Ω

➞ R = 9Ω

Current through 6Ω resistor :

➞ V = IR

➞ 4 = I × 9

➞ 4 ÷ 9 = I

➞ 0.44 = I

• So, current through 6Ω resistor is 0.44 A.

ii) For calculating the potential difference across 12Ω resistor. At first we need to find the resistance of 12Ω and 3Ω, then we will find the current.

➞ R = R₁ + R₂

➞ R = 12Ω + 3Ω

➞ R = 15Ω

Now,

➞ V = IR

➞ 4 = I × 15

➞ 4 ÷ 15 = I

➞ 0.267 = I

★ Potential difference across 12Ω resistor :

➞ V = IR

➞ V = 0.267 × 12

➞ V = 3.2 V

• So,the potential difference across 12Ω resistor is 3.2 V.

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Answer 2

Given :-

R1 = 6 Ω

R2 = 3 Ω

R3 = 3 Ω

R4 = 12 Ω

V = 4 V

To Find :-

(i) Find the current through 6 ohm resistor.

(ii) find the potential difference across 12 ohm resistor

Solution :-

a)

Since

R1 and R2 are in series

Therefore

Equivalent resistance = 6 + 3

Equivalent resistance = 9 Ω

Now

V = IR

Where

V = Potential difference

I = Current

R = Resistance

4 = I(9)

4/9 = I

0.44 = I

b)

Since R3 and R4 are also in series

Equivalent resistance = 12 + 3

Equivalent resistance = 15 Ω

Now

V = IR

Where

V = Potential difference

I = Current

R = Resistance

4 = I(15)

4/15 = I

0.26 = I