Question

i Find the least number which when dluded by 615 and 18. lemes esminde 5 in each case ​

Answer 1

Hey dear... there are many mistakes in your questions

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$\huge\color{cyan}\boxed{\colorbox{black}{Question❤}}$

Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case.

$\huge\color{cyan}\boxed{\colorbox{black}{Answer❤}}$

$\huge\color{cyan}\boxed{\colorbox{black}{95}}$

$\huge\color{cyan}\boxed{\colorbox{black}{Solution❤}}$

L.C.M of 6, 15, and 18 is 90

using Prime Factorization

=> 6 = 2 × 3

=> 15 = 3 × 5

=> 18 = 2 × 3 × 3

Therefore ,

L.C.M of 6, 15 and 18 = 2 x 3 x 3 x 5 = 90

As we need 5 in each case, we will add it with 90

the required number = 90+5 = 95

$\huge\color{cyan}\boxed{\colorbox{black}{Verification}}$

1) Dividing by 6

$\huge\frac{95}{6}$

Quotient = 15

Remainder = 5

2) Dividing by 15

$\huge\frac{95}{15}$

Quotient = 6

Remainder = 5

3) Dividing by 18

$\huge\frac{95}{18}$

Quotient = 5

Remainder = 5

Hence ,all are varified

Therefore ,95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case.

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