Question

i. Find the nature of the roots of the quadratic
equation 3x2 - 413x + 4 =0.​

Answer 1

Answer:

Real and unequal

Step-by-step explanation:

Comparing the equation with ax2 + bx + c = 0,

a=3, b= -413, c=4

b^2-4ac= (-413)^2 + 4 × 3 × 4

= 170569 + 48

= 170617

b^2-4ac > 0

Therefore, roots are real and unequal

Mark me as brainliest pls