Question

(i) Find the probability, first boy pick the card and he get the card with an even number?
(ii) If all cards drawn are replaced then what is the probability of getting multiple of 3 and 5?​

Answer 1

Answer:

I) 10/20 = 1/2

ii) 9/20

Step-by-step explanation:

I) since there are total of 20 numbers the denominator will be 20.

since there are 10 even numbers the numerator will be 10

ii) since there are a total of nine multipliers of 3 and 5 the numerator will be

Answer 2

(i) The probability, first boy pick the card and he get the card with an even number = 1/2.

(ii) If all cards drawn are replaced then the probability of getting multiple of 3 and 5? = 1/20.

Given:

one day, during games period four friends A,B,C and D planned to play game using number cards.

They prepared 20 numbered cards with labelled 1 to 20 and then they put all the number cards in the empty chalk box available in the class room.

Every friend was asked to pick the card randomly and after each draw, card was replaced back in the chalk box.

To Find;

(i) Find the probability, first boy pick the card and he get the card with an even number?

(ii) If all cards drawn are replaced then what is the probability of getting multiple of 3 and 5?​

Solution:

(i) The probability, first boy pick the card and he get the card with an even number = 1/2.

(ii) If all cards drawn are replaced then the probability of getting multiple of 3 and 5? = 1/20.

Probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one. Probability has been introduced in Maths to predict how likely events are to happen. The meaning of probability is basically the extent to which something is likely to happen. This is the basic probability theory, which is also used in the probability distribution, where you will learn the possibility of outcomes for a random experiment.

Formula Used: Probability of event to happen P(E) = Number of favourable outcomes/Total Number of outcomes

(i) Number of possible outcomes = 20

Number of favourable outcomes = {2, 4 , 6, 8, 10, 12, 14, 16, 18, 20}

i.e, 10

P(even number) = 10/20 = 1/2

(ii) Number of possible outcomes = 20

Number of favorable outcomes = {15} i.e, 1

P(multiple of 3 and 5?) = 1/20

(i) The probability, first boy pick the card and he get the card with an even number = 1/2.

(ii) If all cards drawn are replaced then the probability of getting multiple of 3 and 5? = 1/20.

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