Question

i) Find the product (2m+4n) (3m-2n)​

Answer 1

Step-by-step explanation:

2m(3m-2n)+4n(3m-2n)

6m^2 -4mn + 12mn -8n^2

6m^2+8mn-8n^2

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Answer 2

∴(3m−4n)(2m−3n)

=3m×(2m−3n)−4n×(2m−3n)

=[(3m×2m)−(3m×3n)]−[(4n×2m)−(4n×3n)]

=(6m2−9mn−8mn+12n2)

=(6m2−17mn+12n2)

Hence, (3m−4n)(2m−3n)=6m2−17mn+12n2