Question

I. Find the product of the following pairs of monomials:
1) a, a
2)-86pq, -25p
3) 14 xy", -11x'y?
pls say the answer fast it is very urgent.....​

Answer 1

Answer:

$\sf1)a \times a = {a}^{2}$

$\sf2) - 86pq \times - 25q = 2150p {q}^{2}$

$\sf3)14xy \times - 11xy = −154 {xy}^{2}$

Answer 2

1. a × a = a square ..............

2. - 86 pq × - 25q = 2150 pq square

3. 14 xy × - 11xy = - 154xy square