Question

I find the rootsof the following quadratic equations by factorisation
x2-10x-96​

Answer 1

Answer:

x^2 - 10x -96

==> x^2 -16x + 6x - 96

==>x(x-16) + 6(x-16)

==>(x-16)(x+6)

∴ roots are -6 and +16

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Answer 2

Answer:

The roots of the quadratic equation x²-10x-96 are 16,-6

Step-by-step explanation:

x²-10x-96

=>x²-(16x-6x)-96

=>x²-16x+6x-96

=>(x²-16x)+(6x-96)

=>x(x-16)+6(x-16)

=>(x-16)(x+6)

=>x=16,-6

HOPE THIS ANSWER HELPS YOU OUT .