Question

(i) Find the side of a square whose diagonal is 10 cm.​

Answer 1

Answer:

I think it may help you.

Answer 2

Answer:

here ABCD is a square

as , diagonals of square are equal and bisect each other at 90°

from this we can say that

AC=BD= 10 cm

1/2AC= 1/2 BD=5cm

AO=CO=BO=DO= 5cm

and

angle AOB= angle BOC = angle COD = angle DOA = 90°

in , ∆AOB

as, angle AOB =90°

therefore, (AB)sq = (BO)sq + (AO)sq { Pythagoras theorem}

(AB)sq= 5*5 + 5*5

${ab} = \sqrt{25 + 25}$

$ab = \sqrt{50}$

AB = 5√2 cm

as,

Area is square = side * side

5√2*5√2

50cm square

I hope it has helped you