Math, asked by ShreyaWon, 6 days ago

(i) Find the simple interest of ₹300 in 3 years at 3% rate of interest per annum.

(ii) Find the simple interest and amount of the sum of ₹800 in 3 years at 5% rate of interest per annum.

(I will mark you as well list if you answered those two questions correctly)​

Answers

Answered by Anonymous
12

 \qquad \qquad \; \large {\underline{\underline{\pmb{\pink{\sf{ Question \; 1 }}}}}}

Given :

  • Principal = Rs.300
  • Rate = 3 %
  • Time = 3 years

 \\ \\

To Find :

  • Simple Interest = ?

 \\ \\

Solution :

 \dag Formula Used :

  •  {\underline{\boxed{\pmb{\sf{ S.I = \dfrac{P \times R \times T }{100} }}}}}

Where :

  • ➳ S.I = Simple Interest
  • ➳ P = Principal
  • ➳ R = Rate
  • ➳ T = Time

 \\ \qquad{\rule{150pt}{1pt}}

 \dag Calculating the Interest :

 {\longmapsto{\qquad{\sf{ S.I = \dfrac{P \times R \times T }{100} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ S.I = \dfrac{300 \times 3 \times 3}{100} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ S.I = \dfrac{900 \times 3}{100} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ S.I = \dfrac{2700}{100} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ S.I = \cancel\dfrac{2700}{100} }}}} \\ \\ \\ \ {\qquad \; \; {\therefore \; {\underline{\boxed{\red{\pmb{\frak{ Simple \; Interst = ₹ \; 27 }}}}}}}}

 \\ \qquad{\rule{150pt}{1pt}}

❛❛ Simple Interest on this sum of money is ₹ 27 .❜❜

 \\ {\underline{\rule{300pt}{9pt}}}

 \qquad \qquad \; \large {\underline{\underline{\pmb{\pink{\sf{ Question \; 2 }}}}}}

Given :

  • Principal = Rs.800
  • Rate = 5 %
  • Time = 3 years

 \\ \\

To Find :

  • Simple Interest = ?

 \\ \\

Solution :

 \dag Formula Used :

  •  {\underline{\boxed{\pmb{\sf{ S.I = \dfrac{P \times R \times T }{100} }}}}}

Where :

  • ➳ S.I = Simple Interest
  • ➳ P = Principal
  • ➳ R = Rate
  • ➳ T = Time

 \\ \qquad{\rule{150pt}{1pt}}

 \dag Calculating the Interest :

 {\longmapsto{\qquad{\sf{ S.I = \dfrac{P \times R \times T }{100} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ S.I = \dfrac{800 \times 5 \times 3}{100} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ S.I = \dfrac{4000 \times 3}{100} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ S.I = \dfrac{12000}{100} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ S.I = \cancel\dfrac{12000}{100} }}}} \\ \\ \\ \ {\qquad \; \; {\therefore \; {\underline{\boxed{\purple{\pmb{\frak{ Simple \; Interst = ₹ \; 120 }}}}}}}}

 \\ \qquad{\rule{150pt}{1pt}}

❛❛ Simple Interest on this sum of money is 120 . ❜❜

 \\ {\underline{\rule{300pt}{9pt}}}

Answered by pappuparsad722
0

Answer:

p=300

t=3yers

r=3%

according to formula

300×3×3/100

= 27 is a simple interest

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