I find the value of m and not for which the following system of linear equations has infinitely many solutions 3x+4y =12 (m+n)x-2 (m-n) y= (5m -1).
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3x+4y=12
(0,3)
So,(m+n)x-2(m-n)y=(5m-1)
= (m+n)0-2(m-n)3=(5m-1)
= 0-2(3m-3n)=(5m-1)
= -6m+6n=(5m-1)
= 6n=5m-1+6m
= 6n=11m-1
= n=11m-1/7
3x+4y=12
(4,0)
(0,3)
So,(m+n)x-2(m-n)y=(5m-1)
= (m+n)0-2(m-n)3=(5m-1)
= 0-2(3m-3n)=(5m-1)
= -6m+6n=(5m-1)
= 6n=5m-1+6m
= 6n=11m-1
= n=11m-1/7
3x+4y=12
(4,0)
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