Question

I Find the value of y
$( \frac{ {11}^{ - 10} }{15} ) \times ( \frac{ {11}^{5} }{15} ) = ( \frac{ {11}^{ - 5y} }{15} )$
find value of y​

Answer 1

$we \: know \\ \\ \frac{11 {}^{ - 1 0 } }{15} \: \: \times \: \: \frac{11 {}^{5} }{15 } \: \: = \frac{11 {}^{ - 5y} }{15} \\ \\ computing \: lhs \: value \\ \\ \frac{11 {}^{ - 10 + 5} }{15} = \frac{11 {}^{ - 5y} }{15} \\ \\ = \frac{11 {}^{ - 5} }{15} \: = \: \frac{11 {}^{ - 5 y{}} }{15} \\ \\ comparing \: values \: and \: cancelling \: terms \\ \\ 11 {}^{ - 5} = 11 {}^{ - 5y} \\ \\ - 5 = - 5y \\ \\ \maltese \: \: \huge \mathfrak \red {y = 1}$

Answer 2

Step-by-step explanation:

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