Question

(i) Find three consecutive numbers whose sum is 108.

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Answer 1

Answer: first no. = 35

              second no. = 36

              third no. = 37

Step-by-step explanation: let first no. be x

                                             second no. = x + 1

                                             third no. = x + 2

                                             A.T.Q

                                             x + x + 1 + x + 2 = 108

                                             3x + 3 = 108

                                             3x = 108 - 3

                                             3x = 105

                                             x = 105/3

                                             x = 35

                                             first no. = 35

                                             second no. = 36

                                             third no. = 37

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Answer 2

Question:

• Find three consecutive numbers whose sum is 108.

$\sf \underline \purple{ \dag \: given \: clues :}$

• the sum of the consecutive integers equals 108

★To Find:

• the unknown number

Solution:

➜as we don't know the values of the numbers so,

$: \sf\longrightarrow \: let \: the \: first \: number \: be \: \pink x$

as given that, the numbers are consecutive

$: \tt\longrightarrow \: the \: second \: number = \pink{x + 1}$

and,

$: \tt\longrightarrow \: the \: third \: number = \pink{x + 2}$

➺thier sum equals 108 so,

$: \implies \sf \: x + x + 1 + x + 2 = 108 \\ \\ \\ : \implies \sf \: 3x + 3 = 108 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ : \implies \sf3x = 108 - 3 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\: \implies \sf3x = 105 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ : \implies \sf \: x = \cancel\frac{105}{8} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ : \implies \sf \: x = \pink{ \boxed{35} \bigstar} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

as we found the value of x now let's find the other numbers

$: \tt\longrightarrow \: first \: number = 35(x) \: \: \: \: \: \: \: \: \: \: \\ \\ \\ : \tt\longrightarrow \: second \: number =36(x + 1) \\ \\ \\ : \tt\longrightarrow \: third \: number =37(x + 2) \:$

$\blue{ \underline{ \boxed{ \purple{ \mathfrak{ \therefore \:the \: numbers \: are \: 36 \:37 \: 35 }}}}}$