Question

I fold an equilateral triangle so that
one corner touches the middle of the
opposite edge. What is the ratio of
the perimeter of the triangle to the
perimeter of the resulting trapezium?

Answer 1

the side of the triangle is 'a' so perimeter =3a and as this trapezium made of joining the midpts so perimeter of trapezium=a/2+a/2+a/2+a=5a/2...

ratio= 3a:5a/2=6a:5a=6:5