I for an A.P..,t6 =-10 and t14= 34. find the value
of t10.
Answers
Answered by
2
Answer:
t10=5*16/21=80/21
Step-by-step explanation:
t6=6/2 (2a+5d)=-10
2a+5d=-10/3.....................(1)
t14==14/2(2a+13d)=34
2a+13d=34/7....................(2)
adding(1) and (2)
4a+18d=-10/3+34/7=1/21(-70+102)
4a+18d=32/21
or 2a+9d=16/21
thus
t10=5{ 2a+9d)
t10=5*16/21=80/21
Similar questions
Social Sciences,
2 months ago
English,
2 months ago
Math,
2 months ago
Art,
5 months ago
Math,
9 months ago