Question

I for an A.P..,t6 =-10 and t14= 34. find the value
of t10.​

Answer 1

Answer:

t10=5*16/21=80/21

Step-by-step explanation:

t6=6/2 (2a+5d)=-10

2a+5d=-10/3.....................(1)

t14==14/2(2a+13d)=34

2a+13d=34/7....................(2)

adding(1) and (2)

4a+18d=-10/3+34/7=1/21(-70+102)

4a+18d=32/21

or 2a+9d=16/21

thus

t10=5{ 2a+9d)

t10=5*16/21=80/21