Question

I gave 3/16 of my money to A, 1/4 to B and the remaining 36 rupees to C. How much had I and how much did A and B get?​

Answer 1

Answer:

$let \: you \: have \: x \: rupees \\ you \: gave \: money \: to \: a = \frac{3}{16} of \: x \\ = > \frac{3x}{16} \\ you \: gave \: money \: to \: b \: = \frac{1}{4} of \: x \: \\ = > \frac{x}{4} \\ and \: the \: remaining \: rupees \: are \: = 36 \\ so \\ \frac{3x}{16 } + \frac{x}{4} = 36 \\ => \frac{3x + x}{16} = 36 \\ = > \frac{4x}{16} = 36 \\ = > 4x = 16 \times 36 \\ = > x = \frac{16 \times 36}{4} \\ x = 144 \\ \\ you \: gave \: \\ money \: to \: a \: = \frac{3x}{16 } \\ = \frac{3 \times 144}{16} \\ = 27 \\ \\ \\ you \: gave \: money \: to \: b \: = \frac{x}{4} \\ = \frac{144}{4} \\ = 36$

A get 27 rupees .

B get 36 rupees.

hope you can solve it now

Step-by-step explanation:

mark me as a brainliest.