Math, asked by shbo2370, 5 days ago

I gave 5/9th of money to A and 3/7th to B. If B get 16 Rupees less than A. How much did each get?

Answers

Answered by kansalshobhi21
1

Answer:

A get 70 ruppes and B get 54 ruppes

Attachments:
Answered by ajajit9217
0

Answer:

A got Rs. 63 and B got Rs.54

Step-by-step explanation:

Let total money be Rs.x

Amount of money A got = RS. 5/9 of x = 5x / 9

Amount of money  B got = Rs.3/7 of x =3x /7

According to the problem,

5x /9 = (3x/7 ) +16

(5x /9 ) - (3x /7) =16

{(5x × 7 ) - (3x × 9 )} /63 = 16

(35x - 27x )   = 16 ×63

      8x = 1008

         x = 1008 / 8 =126

Amount of money A got = (5× 126 ) /9

                                        = (630 /9)=Rs.63

Amount of money B got = ( 3 × 126 ) /7

                                        =378 / 7 =Rs.54

Similar questions