I gave 5/9th of money to A and 3/7th to B. If B get 16 Rupees less than A. How much did each get?
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Answered by
1
Answer:
A get 70 ruppes and B get 54 ruppes
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0
Answer:
A got Rs. 63 and B got Rs.54
Step-by-step explanation:
Let total money be Rs.x
Amount of money A got = RS. 5/9 of x = 5x / 9
Amount of money B got = Rs.3/7 of x =3x /7
According to the problem,
5x /9 = (3x/7 ) +16
(5x /9 ) - (3x /7) =16
{(5x × 7 ) - (3x × 9 )} /63 = 16
(35x - 27x ) = 16 ×63
8x = 1008
x = 1008 / 8 =126
Amount of money A got = (5× 126 ) /9
= (630 /9)=Rs.63
Amount of money B got = ( 3 × 126 ) /7
=378 / 7 =Rs.54
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