I get confused in the middle of this factorize
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Let us take a²-b²=x
b²-c²=y
c²-a²=z
Here, x³+y³+z³
But we know that x³+y³+z³=3xyz when x+y+z=0
a²-b²+b²-c²+c²-a²=0
Therefore the whole equation equals to
3(a²-b²)(b²-c²)(c²-a²)
We know that x²-y²=(x+y)(x-y)
So factorization would be
3(a+b)(a-b)(b+c)(b-c)(c+a)(c-a)
b²-c²=y
c²-a²=z
Here, x³+y³+z³
But we know that x³+y³+z³=3xyz when x+y+z=0
a²-b²+b²-c²+c²-a²=0
Therefore the whole equation equals to
3(a²-b²)(b²-c²)(c²-a²)
We know that x²-y²=(x+y)(x-y)
So factorization would be
3(a+b)(a-b)(b+c)(b-c)(c+a)(c-a)
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