Question

i given that A=(0,1,3,5); B=(1,2,3,4,7); C=(1,2,3,5,8). prove that (AnB)nC =An(BnC)
ii.(AnB)uC =(AuC)n(BuC)

Answer 1

(Anb)=(1,3)
(Anb)nc=(1,3)n(1,2,3,5,8)
=(1,3)
now,
An(BnC)=(0,1,3,5)n(1,2,3)
=(1,3)

Answer 2

Answer:

Step-by-step explanation:

a={a d f g } b={a b e h } c={a c g i } proof associated low (a n b) n c = a n (b n c)