I had a question which I can't solve. I will be very glad if you help me. Question'- there is a equation K^2(2×a^2 = b^2 + c^2) If "k" is the scaling factor and a,b,c,k belongs to integers and are not equal to each other. Find any non prime value of "a". Or prove it is not possible , and find are there finite or infinite values of "a" which satisfy the equation.
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{ 2 } = a ^ { 2...
a 2 + ( − b) a + b 2 − c 2 = 0. This equation is in standard form: ax^ {2}+bx+c=0. Substitute 1 for a, -b for b, and \left (b-c\right)\left (b+c\right) for c in the quadratic formula, \frac {-b±\sqrt {b^ {2}-4ac}} {2a}. This equation is in standard form: a x 2 + b x + c = 0
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