I had some money in my pocket.I gave one fourth to my friend.I spent one fourth of the starting amount and lost 50 rupees.Now I am left with 10 rupees.How much money did I have initially?
Answers
Answer:
I initially had an amount of Rs.120.
Step-by-step explanation:
Let the money I had be Rs.x
Now, according to the Question,
I gave (1/4)th to my friend,
That is x × (1/4)
= (1/4)x
This is the money I gave my friend, then my remaining money will be,
= x - (1/4)x
Taking the LCM = 4,
= (4/4)x - (1/4)x
= ((4 - 1)/4)x
= (3/4)x
Thus, now I have Rs.(3/4)x.
Again I spent (1/4)th of my original money,
So,
I again spent Rs.(1/4)x
So, the remaining money will be,
(3/4)x - (1/4)x
= ((3 - 1)/4)x
= (2/4)x
= (1/2)x
Now, I lost Rs.50,
Then, my remaining money will be,
(1/2)x - 50
But, according to the Question,
Now, I am left with Rs.10
∴ (1/2)x - 50 = 10
Solving for x,
(1/2)x = 10 + 50
(1/2)x = 60
x = 60 ÷ (1/2)
x = 60 × (2/1)
x = Rs.120
Hence,
I initially had an amount of Rs.120.
Hope it helped and believing you understood it........All the best
Answer:
The amount of money given to friend = \dfrac{1}{4}
4
1
th of total
The amount of money spend = \dfrac{1}{4}
4
1
th of total
The amount of money that was lost = Rs 50
The amount of money left = Rs 10
To Find :
The initial amount of money that he have
Solution :
Let The initial amount of = Rs x
The amount of money given to friend = \dfrac{1}{4}
4
1
th of total
= \dfrac{1}{4}
4
1
× x = Rs \dfrac{x}{4}
4
x
The amount of money spend = \dfrac{1}{4}
4
1
th of total
= \dfrac{1}{4}
4
1
× x = Rs \dfrac{x}{4}
4
x
So, The amount of money left = initial amount of money - ( amount of money given to friend + amount of money spend + amount of money that was lost )
Or, 10 = x - ( \dfrac{x}{4}
4
x
+ \dfrac{x}{4}
4
x
+ 50 )
Or, 10 = x - \dfrac{x}{2}
2
x
- 50
Or, \dfrac{2x - x}{2}
2
2x−x
= 10 + 50
Or, \dfrac{x}{2}
2
x
= Rs 60
∴ x = 2 × Rs 60
i.e x = Rs 120
Hence, The initial amount of money that he had is Rs 120 Answer
Step-by-step explanation:
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