Question

I had some rupee-coins with me of which I gave 1/4th to A 2/5ths to B and the
rest to C. Find the least number of rupees that I had.​

Answer 1

Answer:

Rs.20

Step-by-step explanation:

A =1/4 th , B= 2/5 th

Sum of parts of A and B = 1/4 th + 2/5 th

= (5+10)/20 = 15/20= 3/4 th

C= 1 - 3/4 = 1/4 th

L.C.M. of 4,5 and 4 = 20

least number of rupees= 20