I have 20 different balloons numbered from 1 to 20.
A. If I randomly split the balloons to pairs, when the order is not important,
What is the probability that in each pair there will be an even balloon (2,4,6 etc)
What is the probability that in exactly 2 pairs of balloons there won't be an even balloon
Answers
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Step-by-step explanation:
* Probability of getting even numbered balloon .
even numbers = 2,4,6,8,10,12,14,16,18,20
= (sum of observations) ÷ (number of observations)
= (2+4+6+8+10+12+14+16+18+20) ÷ 10
= (110) ÷ (10)
= 11.
* probability of getting odd numbered balloon.
odd numbers = 1,3,5,7,9,11,13,15,17,19
=( 1+3+5+7+9+11+13+15+17+19) ÷ 10
= (100) ÷(10)
= 10.
* Hence solved .
* I hope this may help you.
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