Question

I have 3x balls of colours Red, Blue and Green. There are exactly x balls of each colour.
These 3x balls are now distributed to 3 boxes such that each box contains exactly x balls. You are given the contents of each box.
You would like the 1st box to contain all the red balls, the 2nd box to contain all the green balls, and the 3rd box to contain all the blue balls. Note that the given order of boxes is important here.
Determine the minimum number of operations required .

Answer 1

Answer:

Let no. of red balls = x, no. of blue balls =y and no.of black balls = z.

Probability of drawing a red ball = P (red ball) =

20

11

=

40

x

⇒ x=22

Probability of drawing a blue ball = P (Blue ball) =

5

1

=

40

y

⇒ y=8

∴ No of black balls = 40- 22 -8 =10