I have a book having dimensions 40cmx30cmx4cm and mass 500g. Find the pressure exerted by it on the table.
(i) When book lies down on the table.
(ii) When book is kept on the table such that it covers 30cmx4cm area of the table.
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Answer : 40.8 and 408.3
Explaination :
First find force exerted on table which is equal to mg. g = 9.8 m/s².
F = mg = 4.9 N
Now in first case:
Area covered by book = 30 * 40 = 1200 cm² = 12 * 10 ^ -2 m².
So P = F / A = 4.9 / 12 * 10 ^ -2 = 40.8
Similarly in second case:
P = 408.33
Please mark it as brainliest if it helps !!!
Thank You.
Explaination :
First find force exerted on table which is equal to mg. g = 9.8 m/s².
F = mg = 4.9 N
Now in first case:
Area covered by book = 30 * 40 = 1200 cm² = 12 * 10 ^ -2 m².
So P = F / A = 4.9 / 12 * 10 ^ -2 = 40.8
Similarly in second case:
P = 408.33
Please mark it as brainliest if it helps !!!
Thank You.
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