I have a box. The top's area is 240 square inches, the front's area is 300 square inches and the end's area is 180 square inches. What are the dimensions of the box?
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The dimensions of the box are:-Length=20, depth=12, height=15.
This is easily solved with a little simple algebra. If we call the three sides A, B, and C we have:
A x B = 240
A x C = 300
B x C = 180
Multiplying these together we get:
(A x B) x (A x C) x (B x C) = 240 x 300 x 180
A2 x B2 x C2 = 12,960,000
(A x B x C)2 = 12,960,000
Which means that:
A x B x C = 3600
Substituting A x B = 240 back in gives C = 15 and the rest follow.
This is easily solved with a little simple algebra. If we call the three sides A, B, and C we have:
A x B = 240
A x C = 300
B x C = 180
Multiplying these together we get:
(A x B) x (A x C) x (B x C) = 240 x 300 x 180
A2 x B2 x C2 = 12,960,000
(A x B x C)2 = 12,960,000
Which means that:
A x B x C = 3600
Substituting A x B = 240 back in gives C = 15 and the rest follow.
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