Question

I have a double in this question

Answer 1

2 5/6 will be the answer.

Answer 2

$\huge{Solution:}$

A worker done work on Monday for $3 \frac{1}{4}$ hrs =

$\frac{13}{4}$

||ly on Tuesday for $2 \frac{1}{2}$ hrs =

$\frac{5}{2}$

On Wednesday for $2 \frac{3}{4}$ hrs =

$\frac{11}{4}$

We know that

Mean = Sum of frequencies/total no. of frequencies

so, Mean no. of hrs he worked =

$(\frac{13}{4} + \frac{5}{2} + \frac{11}{4} ) \div 3$

$= ( \frac{24}{4} + \frac{5}{2} ) \times \frac{1}{3}$

=

$(\frac{12}{2} + \frac{5}{2} ) \times \frac{1}{3}$

=

$\frac{17}{2} \times \frac{1}{3}$

$= \frac{17}{6}$

$= 2 \ \frac{5}{6}$