i have a doubt in surface chemistry.
in the Hardy-Schulze law -'greater the polarizing power of the flocculating ion added, the greater is its power to cause precipitation'
But more the polarizing power smaller is the size of an ion.In that case Na+ should be greater than Ba2+ than Al3+
But the order is vice versa Al3+>Ba2+>Na+
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hardy Schulz rule states that greater the valency if the ion greater is the coagulation power or flocculating power. so the order AL+3,Ba2+,and Na+ is correct
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Answer:
Explanation:
This is because it the drawback of the Hardy Schulz rule that it has taken into consideration the charge of the ion and not the size of the ion and thereby, the polarizability of the ion.
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But the order is vice versa Al3+>Ba2+>Na+