Physics, asked by shasa47, 1 day ago

I have a doubt in the solution of the question below.

If q1 and q2 are two positively charged identical point charges seperated by distance r, then what is the coulomb force when a dielectric slab of thickness t (t<r) is introduced between them?

-My doubt is that while solving this question, we assume that distance of dielectric slab is t√k. Why do we assume it so? Shouldn't it be just t?​

Answers

Answered by meetdchaudhari2006
1

Explanation:

please mark me as the brainliest

Attachments:
Answered by βαbγGυrl
0

Answer:

Initial force between the charges          F=kq1q2/r2

Now distance between charges is doubled and both the charges are also doubled   i.e  q1′=2q1,        q2′=2q2         and        r′=2r

Thus new force    F′=k(2q1)(2q2)/2r2=F

Similar questions