Question

I have a total ₹300 in coins of denomination ₹1 ,₹2 and ₹5. the number of ₹2coins is 3 times the number of ₹5 coins the total number of coins is 160 .how many coins of each denomination are with me ?

Answer 1

Let the number of ₹5 coins = x
the number of ₹2 coins = 3x
the number of ₹1 coins = 160-(3x+x)=160-4x
A/Q
5(x) + 2(3x) + 1(160-4x) = 300
5x + 6x + 160-4x = 300
7x = 300-160
7x = 140
x = 20
hence, the number of ₹5 coins = 20
the number of ₹2 coins = 3×20=60
the number of ₹1 coins = 160-4×20=160-80=80

Answer 2

Let the number of ₹5 coins be x.

Then,

number ₹2 coins = 3x

and, number of ₹1 coins = (160 – 4x) Now,

Value of ₹5 coins = x × 5 = 5x

Value of ₹2 coins = 3x × 2 = 6x

Value of ₹1 coins = (160 – 4x) × 1 = (160 – 4x)

According to the question,

5x + 6x + (160 – 4x) = 300

⇒ 11x + 160 – 4x = 300

⇒ 7x = 140

⇒ x = 140/7

⇒ x = 20

Number of ₹5 coins = x = 20

Number of ₹2 coins = 3x = 60

Number of ₹1 coins = (160 – 4x) = 160 – 80 = 80