Question

i have a total of £300 COINS OF DENOMINATION £1, £2,£5. THE NUMBER OF £2 COINS IS 3 TIMES THE NUMBER OF £5 COINS. THE TOTAL NUMBER OF COINS IS 160. HOW MANY COINS OF EACH DENOMINATION ARE WITH ME

Answer 1

£2 coins = x

£5 coins = y

x = 3y (given)

x + y = 160 (given)

3y + y = 160

4y = 160

y = 160/4 = 40

x = 160 - 40 = 120

£1 coins = 300 - 160 = 140

£2 coins = 120

£5 coins = 40

Answer 2

Answer:

Total no. of coins = 160

The no. of 5 rs coins be x

The no. of 2 rs coins be 3x

The no. of 5 rs coins be 4x

The no. of coins => 1 coins 160 - ( 3x + x)

= 160 - 4x

Amount of 5 rs coins = 5x

Amount of 2 rs coins = 2x × 2 = 6x

Amount of 1 rs coin = 60 - 4x

.•. -> 5x + 6x + 160 - 4x = 300

-> 11x + 160 - 4x = 300

-> 7x + 160 - 4x + 160 = 300

-> 7x = 140

-> x = 140 / 7 = 20