Question

I have a total of $300 in coins of denomination $ 1, $ 2 and $ 5. the number of $2 coins is 3 times the number of $5 coins. the total number of coins is 160 .how many coins of each denomination are with me?​

Answer 1

Answer:

No. of $5 coins = 20

No. of $2 coins = 20×3 = 60

No. of $1 coins = (160-20-60) = 160-80 = 80

Step-by-step explanation:

Let the no. of $5 coins be x, $2 coins be 3x and $1 coins be (160-x-3x).

Then, A/q

$5(x)+$2(3x)+$1(160-x-3x) = $300

5(x)+2(3x)+1(160-x-3x) = 300

5x+6x+160-x-3x = 300

5x+6x-x-3x = 300-160

11x-4x = 140

7x = 140

x = [yex\frac{140}{7}[/tex]

x = 20

Hence, No. of $5 coins = 20

No. of $2 coins = 20×3 = 60

No. of $1 coins = (160-20-60) = 160-80 = 80

Hope it helps you ✌️

Answer 2

Step-by-step explanation:

BRO your answer is here.