i have a total of₹300 in coins of denomination 1 2and 5 the numbers of 2 coins is 3times the number of₹5 coins the total number of coins is 160 how many each denomination are with me
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Answer:
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8th
Maths
Linear Equations in One Variable
Solving Linear Equations in One Variable
Ravi works as a cashier in ...
MATHS
Ravi works as a cashier in a bank. He has currency of denominations Rs.100, Rs.50, Rs.10 respectively. The ratio of the number of these notes is 2:3:5.
The total cash with Ravi is Rs.4,00,000.
How many notes of cash of each denominations does he have?
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ANSWER
Let the number of Rs.100 notes =2x
Number of Rs.50 notes =3x
And Number of Rs.10 notes =5x
∴ Total Money =(2x×100)+(3x×50)+(5x×10)
200x+150x+50x=400x
But according to the problem the total money is Rs.4,00,000
⇒ 400x=4,00,000
x=
400
400000
=1000
Therefore number of Rs.100 notes 2x=2×1000=2000
Number of Rs.50 notes =3x=3×1000=3000
Number of Rs.10 notes =5x=5×1000=5000
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Answer:
Let the number of ₹5 coins be x.
Then,
number ₹2 coins = 3x
and, number of ₹1 coins = (160 – 4x) Now,
Value of ₹5 coins = x × 5 = 5x
Value of ₹2 coins = 3x × 2 = 6x
Value of ₹1 coins = (160 – 4x) × 1 = (160 – 4x)
According to the question,
5x + 6x + (160 – 4x) = 300
⇒ 11x + 160 – 4x = 300
⇒ 7x = 140
⇒ x = 140/7
⇒ x = 20
Number of ₹5 coins = x = 20
Number of ₹2 coins = 3x = 60
Number of ₹1 coins = (160 – 4x) = 160 – 80 = 80