I have a total of Rs.300 in coins of denomination Rs.1 , Rs.2 and Rs.5 The number of Rs.2 coins is 5 times the number of Rs.1 coins. The total number of coins is 250 . How many coins of each denomination are with me ?
Answers
let the no. of rs 5 coins be x
& the no. of rs 1 coin be y
& no. of rs 2 coins be 3x
a.q.t
total no. of coins = 160
x + 3x+y = 160
4x + y = 160..... eq. 1
again a.q.t
total rs = 300
5x + 2(3x) + 1y = 300
11x + y = 300..... eq. 2
by elimination method
(on subtracting both the equations)
4x + y = 160
-11x -y = -300
=-7x =-140
x =20
on putting the the value of x in eq 2
4(20) + y =160
80 + y = 160
y =80
now,
no of rs 2 coins = 3(20)
= 60
no. of rs 5 coins = 20
no. of rs 1 coins=80
plz mark it as brainliest...
let the no.of rs.5 coin be × by no.of rs.2 will be 3×. Rs 1 coin be 160-3×-×= 160-4×. the amount I have . from rs 2 coins =3×=3×2=6× from rs 5 coins= ×=5×. from rs 1 coin=(160-4×)×1=160-4×. total money =30, 6× + 5× +160- 4× =30,7× + 160=300, 7×=140,×=20. no.of rs 2. coins =3×20=60, no.of rs 5 coins =×=20, no.of rs1coin=160-4×20=80.