Math, asked by gulaasiya5, 4 months ago

i have a total of Rs 300 in coins of denomination Rs1,Rs2,Rs5.the no of Rs 2 is 3 times the no of Rs 5 coins. the total no of coins is 160. how many coins of each denomination are with me.please ans​

Answers

Answered by Pratyakshajanga
2

Answer:

Let number of Rs5 coins be x

Number of Rs 2 coins =3× Number of 5 Rs coins =3x

Number of Rs1 coins =160−(x+3x)

=160−4x

Amount of Rs5 coins =5×x=5x

Amount of Rs2 coins =2×3x=Rs6x

Amount of Rs1 coins =(160−4×x)

=160−4x

As per the question, Total amount =Rs300

160−4x+5x+6x=300

7x=300−160

x=  7/140

​x=20

Number of Rs 1 coins =160−4x

=160−4×20=80

Number of Rs2 coins =3x=3×20=60

Number of Rs5 coins =x=20

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Answered by anoosh786
0

Answer:

here u go :)

Step-by-step explanation:

15: Let the number of Rs 5 coins be x

Number of Rs 2 coins = 3 × Number of Rs 5 coins = 3x

Number of Re 1 coins = 160 − (Number of coins of Rs 5 and of Rs 2)

= 160 − (3x + x) = 160 − 4x

Amount of Re 1 coins = Rs [1 × (160 − 4x)] = Rs (160 − 4x)

Amount of Rs 2 coins = Rs (2 × 3x) = Rs 6x

Amount of Rs 5 coins = Rs (5 × x) = Rs 5x

It is given that the total amount is Rs 300.

∴ 160 − 4x + 6x + 5x = 300

160 + 7x = 300

7x = 300 - 160

7x = 140

7x =

x = 20

Number of Re 1 coins = 160 − 4x

= 160 − 4 × 20

= 160 − 80 = 80

Number of Rs 2 coins = 3x

= 3 × 20 = 60

Number of Rs 5 coins = x

= 20

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