Question

I have a total of rs 300in coins of denomination re 1, re 2 and re 5. The number of rs 2 coins is 3 times the number of rs 5 coins . The total number of coins is 160. How many coins of each denomination are with me ?explain it fully .

Answer 1

Answer:

Number of rs. 2 coins = 60

No. of rs 5 coins = 20

No. of rs 1 coins = 80

Step-by-step explanation:

Let the no. of rs 5 coins be x

& the no. of rs 1 coin be y.

& no. of rs 2 coins be 3 x

a.q.t

Total no. of coins = 160

Then,

x + 3x+y = 160

4x + y = 160 .....eq. 1

again a.q.t

total rs. = 300

5x + 2(3x) + 1y = 300

11x + y = 300 ......eq. 2

by elimination method

on subtracting both the equations

4x + y = 160

-11x -y = -300

= -7x =-140

= x =20

on putting the the value of x in eq 2

4(20) + y =160

80 + y = 160

y = 80

now,

No. of rs 2 coins = 3(20)

Number of rs. 2 coins = 60

No. of rs 5 coins = 20

No. of rs 1 coins = 4(20) = 80

Answer 2

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