Question

I have a two-digit number. The unit's digit is twice as ten's digit if i reverse the number and subtract 36 from it, i get the initial number. What's the number started with?

Answer 1

Answer:

The Original Number is 48.

Step-by-step explanation:

Given :

Unit's digit is = twice as ten's digit

Original number is the result when = reversed number is being subtracted by 36

To find :

The Original Number

Solution :

Original Number -

Let the -

• Units Place be 2x
• Tens Palce be 10(x)

Original Number = 10(x) + 2x

➙ 10x + 2x

➙ 12x ....... [Original Number]

$\rule{300}{1.5}$

Number with Reversed Digits -

Let the -

• Units Place be as x
• Tens place be as 10(2x)

Number = 10(2x) + x

➙ 20x + x

➙ 21x ....... [Number with Reversed Digits]

$\rule{300}{1.5}$

According to find the Question -

When 36 is subtracted form number with Reversed Digits, we get the original number.

➙ 21x - 36 = 12x

➙ 21x - 12x = 36

➙ 9x = 36

➙ x = 36/9

➙ x = 4

$\rule{300}{1.5}$

As we got the value of x, we can now find the original number.

➙ Original Number = 12x

➙ 12(4)

➙ 48

$\therefore$ The Original Number is 48.

Answer 2

Answer:

4

Step-by-step explanation:

tricky question.....