Question

I have about plz help plz I have text tomm​

Answer 1

Step-by-step explanation:

In a rhombus diagonals are angle bisectors.

$\therefore \: \angle BAD= 2 \times \angle \: BAC \\ = 2 \times 44 \degree \\ = 88 \degree \\ \\ \because \: \angle \: BCD= \angle \: BAD \\(Opposite \:angles\: of \:rhombus) \\ \huge\boxed {\therefore \: \angle \: BCD = 88 \degree} \\</p><p>\because \angle ADC + \angle BCD = 180\degree\\(Adjacent \:angles\: of \:rhombus) \\</p><p>\therefore \angle ADC + 88\degree = 180\degree \\</p><p>\therefore \angle ADC = 180\degree -88\degree \\</p><p>\huge\boxed {\therefore \angle ADC = 92\degree} \\</p><p>$