I have another question for guys..
A trolley having mass 1kg and traveling at 6m/s strikes and stick another trolley having 10kg.
If the later trolling was initially at rest.
Estimate their common velocity after impact.
Answers
Answered by
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use conservation of momentum
m1u1+m2u2=m1v1+m2v2
1*6+10*0=(1+10)v
6/11=v(common velocity)
hmanface:
V= 0.545m/s^-1
6/11 is 0.545
I have another question
ya ask
An object of mass 3kg rest on a plane. The coefficient of static friction and that of kinetic friction are given by μs = 0.3 and μk = 0.2. The plane inclined at an angle θ at the horizontal.
(a) Find the maximum value of the θ for which the object remains at rest.
(b) find the acceleration of the object of it started sliding from rest down the plane at the angle θ maximum to horizontal.
(c) how long does it take the object to move from rest, a distance of 1 m under the condition of B
(a) Find the maximum value of the θ for which the object remains at rest.
(b) find the acceleration of the object of it started sliding from rest down the plane at the angle θ maximum to horizontal.
(c) how long does it take the object to move from rest, a distance of 1 m under the condition of B
first is tan theta
acceleration is (g sin theta-u g cos theta)
now u have acceleration and initial velocity 0. so u cm solve the last part now
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