Question

I Have asked this question many time but no one answers...please help
Kamal bought 5 apples and 10 bananas at Rs 360.

He sells the apple at a profit of 25% and banana at
loss of 5%. If his overall profit was Rs
54 find the cp of a apple and a banana.​​

Answer 1

The the cost price of apple be Rs. x and cost price of the banana be Rs. y

According to the problem,

5x + 10y = 360

x + 2y = 72 ........(1)

Apple is sold at a gain of 25%

We have selling price = $\frac{100+gainpercentage}{100} cp$

s.p of apple = $\frac{125}{100}x$

Banana is sold at a loss of 5%

s.p of banana = $\frac{100-loss percentage}{100}cp$

s.p of banana = $\frac{95}{100}y$

His profit is Rs 54

Total sale price = 360 + 54

                          = 414

414 =  $\frac{125}{100}x$  +  $\frac{95}{100}y$

41400 = 125x + 95y

8280 = 25x + 19y.........(2)

(1)×25 ⇒ 25x + 50y = 1800..........(3)

Solving equations (2) and (3)

31y = -6480

But cost price can never be negative

Hence the condition in the question cannot be satisfied

HOPE IT HELPS !!