Math, asked by OPBROOP, 1 month ago

i have asked this same question third time
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Answered by kamalhajare543
12

Answer:

 \sf \:  \bold{1).}The \:  Co-ordinate  \: of  \: point  \: S \:  is \:  \boxed{( \bold{-1})}

\bold{2). } \sf \: d \: (U,B) =  \boxed{ \:  \: -4,2 \:  \: }

  \bold{3.}\sf \: The  \: point  \: equidistant  \: from \:  point   \\ \: \sf R  \: is  \: point \:  \boxed{ \: -3 \: }  \: And  \: point \:  \boxed{ \: 3 \: }

 \bold{4.} \sf \: The  \: Ray \:  RP  \: is \:  \sf \: opposite  \: of \\  \: \sf Ray \boxed{ \sf \: R,T/{P,B}}

5.) The intersection set of ray AS ans ray AQ is [(0,-1),(0,1).

Answered by AAnand2000
0

Answer:

1) (-1,0)

2) d(U, B) = 4 + 2 = 6

3) B and C at unit distance

4) Ray RP is opposite to ray PR, many more rays are possible like UT, ray TS etc.

5) A, both intersect at point A

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